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";s:4:"text";s:3953:"NaBH4 cannot reduce these compounds into alcohols but LiAlH4 can.

Primary alcohols are obtained from aldehydes , and secondary from ketones . NaBH4 can handle esters, but it is very slow at converting them and thus not preferable. This is video 6 in the Organic Chemistry Oxidation/Reduction video series.

My teacher told - "To reduce carboxylic acid to alcohol, $\ce{LiAlH4}$ is used. This is the main difference between LiAlH4 and NaBH4. In combination with CeCl 3 allows for selective reductions of α,β-unsaturated carbonyls without reacting with С=С-bonds. what type of functional groups can LiAlH4 reduce? I asked that we can also use $\ce{NaBH4}$ as it also contains 4 hydrogen bonds. Note!

Despite the fearsome names, the structures of the two reducing … But since $\ce{LiAlH4}$ is an expensive reagent, it is commercially reduced by forming an ester and then to alcohol". But, it is a mild reducing agent which cannot reduce esters, amides and carboxylic acids.

If you protect the ketone as an acetal, then you can reduce the ester and, on workup, synthesize the keto alcohol.

Lithium chloride and sodium borohydride dissolved in diethylene glycol dimethyl ether form the intermediate LiBH4 which, unlike NaBH4 , can reduce esters and epoxides.

Reduction of aldehydes and ketones.

NaBH4 is much gentler and cannot reduce esters - - this is convenient because it gives you a choice.

Both LiAlH4 and NaBH4 are important reducing agents in organic synthesis mechanisms.

The key difference between LiAlH4 and NaBH4 is that LiAlH4 can reduce esters, amides and carboxylic acids whereas NaBH4 cannot reduce them..

So, NaBH4 can reduce only aldehydes, ketones, and acyl halides, as you said, due to the greater localization of positive charge on the carbonyl carbon than in esters and carboxylic acids, which must be reduced with the more powerful LiAlH4.
The most common sources of the hydride nucleophile are lithium aluminium hydride (LiAlH 4) and sodium borohydride (NaBH 4). Reduction of aldehydes [NaBH4] Reduction of aldehydes [NaBH4] Definition: Addition of sodium borohydride, NaBH4 to aldehydes gives primary alcohols (after adding acid). Sodium borohydride (NaBH4) is a mild reducing agent that is typically used to reduce aldehydes and ketones to their respective alcohols. This video breaks down the reducing agent NaBH4 to help you understand its reactivity with carbonyl compounds. The reducing agents.

Lithium chloride and sodium borohydride dissolved in diethylene glycol dimethyl ether form the intermediate LiBH4 which, unlike NaBH4 , can reduce esters and epoxides.

Sodium borohydride is a white to grayish crystalline powder.

Sodium borohydride is a relatively selective reducing agent. The reduction of unsymmetrical ketones with LiAlH4 or NaBH4 produces a pair of stereoisomers because the hydride ion can attack either face of the planar carbonyl group: If no other chiral center are present, the product is a racemic mixture of enantiomers . ketones, aldehydes, acid chlorides, esters, carboxylic acids, amides, and nitriles (R-C=N) ---> R-NH2 (which is an amide). 27, 33 Reduction of aldehydes is straightforward. The most common sources of the hydride nucleophile are lithium aluminium hydride (LiAlH 4) and sodium borohydride (NaBH 4). Although LiAlH4 can reduce alot of compounds what type of functional groups can it not reduce? In this case you get the hydroxy ester. ... before the alcohol product can be isolated. It is decomposed by water to form sodium hydroxide, a corrosive material, and hydrogen, a flammable gas.The heat of this reaction may be sufficient to ignite the hydrogen.The material itself is easily ignited and burns vigorously once ignited. SODIUM BOROHYDRIDE Reduces aldehydes and ketones to corresponding alcohols. The difference between LiAlH4 and NaBH4 is that …
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